Very Secure

Why, with 2 cards missing, the odds of a 1-1 break are 52 percent instead of 50 percent.

With 2 cards missing, let's say the K and the 2, it's easy to mislead oneself by drawing conclusions from the following table of all possibilities of the missing cards:

K 2
K2
K2
2 K

The erroneous conclusion is that an even split is equally likely to a king onside. The above table lists all the possible layouts of the suit in question, but it does not take into account the rest of the deal.

For any deal, once you see the dummy, there are 26C13 ways the remaining cards can be laid out against you.

If LHO has the K, and the other the 2, there are 24C12 more cards you can give to LHO. For every hand thus given, you can swap the king and the 2, so the number of hands where the drop is right is 2 * 24C12.

If the finesse is right, then either a specific player has the K and the 2, 24C11 deals, or the singleton king is onside, which accounts for another 24C12 more deals.

So it is sightly better to play for the drop, given no other information.

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